10x=(3x^2)/2x

Solution for 10x=(3x^2)/2x equation:

10x=(3x^2)/2x

We move all terms to the left:

10x-((3x^2)/2x)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We get rid of parentheses

-3x^2/2x+10x=0

We multiply all the terms by the denominator


-3x^2+10x*2x=0

Wy multiply elements

-3x^2+20x^2=0

We add all the numbers together, and all the variables

17x^2=0

a = 17; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·17·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{34}=0$